(a + 1)^3 / a^3 + 1
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On the top I have a^3 + 3a^2 + 3a + 1 and on the bottom I have a^3 + 1, I am not sure where to go from here.
Originally Posted by stellina_91 Simplify..
(a + 1)^3 / a^3 + 1 Factorise the denominator using the sum of two cubes formula. Then cancel out the common factor in the numerator and denominator.
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