You have to isolate the x, of course.Originally Posted bykingkaisai2

2x +1 = xLogA

Divide both sides by x,

(2x +1)/x = LogA

2x/x +1/x = LogA

2 +1/x = LogA

1/x = LogA -2

Since Log(10) = 1, then,

1/x = LogA -2Log(10)

1/x = LogA -Log(10^2)

1/x = LogA -Log(100)

1/x = Log(A/100)

1/x = Log(0.01A)

Take the reciprocals of both sides,

x = 1 / Log(0.01A) -------------------------answer.