Fraction Problem

**Itsbaxagain** · March 9th 2008, 10:59 AM

Man I dislike these fractions but I am having problems finding the answer to this one. $\frac{5}{2x}-\frac{4}{2x^2+3x}$

The site helps me a lot and I haven't found a math site that has help me as much as this one. Even if i am just reading someone threads or doing mine I find help in it somewheres.

**topsquark** · March 9th 2008, 11:07 AM

Originally Posted by Itsbaxagain

Man I dislike these fractions but I am having problems finding the answer to this one. $\frac{5}{2x}-\frac{4}{2x^2+3x}$

The site helps me a lot and I haven't found a math site that has help me as much as this one. Even if i am just reading someone threads or doing mine I find help in it somewheres.

Are you supposed to subtract the fractions?

You need a common denominator. Note that the denominator of the second term is $2x^2 + 3x = x(2x + 3)$ . The LCM of $x$ and $x(2x + 3)$ is $2x(2x + 3)$ .

So....
$\frac{5}{2x} - \frac{4}{2x^2+3x}$

$= \frac{5}{2x} \cdot \frac{2x + 3}{2x + 3} - \frac{4}{2x^2+3x} \cdot \frac{2}{2}$

$= \frac{5(2x + 3) - 2 \cdot 4}{2x(2x + 3)}$

$= \frac{10x + 7}{2x(2x + 3)}$

-Dan

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