1. ## Two Logarithm Problems

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2.) [LaTeX ERROR: Convert failed]

2. Originally Posted by currypuff

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1.)
$2~ln(x - 1) - 2~ln(x) = 0$

[tex]ln((x - 1)^2) - ln(x^2) = 0

$ln((x - 1)^2) = ln(x^2)$

$(x - 1)^2 = x^2$
etc.

2.)
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Take the logarithm of both sides. Any base will do. I'll use base e.
$ln \left ( 6^{5x + 3} \right ) = ln \left ( 2^{x - 2} \right )$

$(5x + 3)~ln(6) = (x - 2)~ln(2)$
etc.

-Dan

3. Thanks, Dan. I worked through the second problem and ended up with x = 0.483. However, I am still uncertain what the next steps are for the first problem. Do you know what the next steps are, after $(x-1)^2=x^2$? Thanks for your help