Hey I'm having problems figuring out how to do this surd.
16/(√20+√12)
I know the answer is 4(√5-√3) but can you plz give me a step by step answer on how to do this...thanks.
Multiply both top and bottom by $\displaystyle \sqrt{20}-\sqrt{12}$:Originally Posted by digideens
$\displaystyle
\frac{16}{\sqrt{20}+\sqrt{12}}=\frac{16(\sqrt{20}-\sqrt{12})}{(\sqrt{20}+\sqrt{12})(\sqrt{20}-\sqrt{12})}
$
$\displaystyle
=\frac{16(\sqrt{20}-\sqrt{12})}{20-12}=4(\sqrt{5}-\sqrt{3})
$
RonL
Yes,Originally Posted by digideens
You have,
$\displaystyle \frac{16(\sqrt{20}-\sqrt{12})}{8}$
Simplyfy fraction to $\displaystyle 2(\sqrt{20}-\sqrt{12})$
Now,
$\displaystyle \sqrt{12}=\sqrt{4\cdot 3}=2\sqrt{3}$
$\displaystyle \sqrt{20}=\sqrt{4\cdot 5}=2\sqrt{5}$
Thus,
$\displaystyle 2(2\sqrt{5}-2\sqrt{3})$
Factor the two,
$\displaystyle 4(\sqrt{5}-\sqrt{3})$