# Solving Linear Equations

• Mar 8th 2008, 09:58 PM
stellina_91
Solving Linear Equations
Solve:

$
\frac{3}{4} - \frac{x + 1}{12} = \frac{2}{3} - \frac{x - 1}{6}
$

Multiplying by 12 you get:

9 - x + 1 = 8 - 2(x - 1)
10 - x = 8 - 2x + 2
10 - x = 10 - 2x
10 + x = 10

Therefore x = 0

The answer says x = 2, I don't know where I went wrong.
• Mar 8th 2008, 10:20 PM
mr fantastic
Quote:

Originally Posted by stellina_91
Solve:

$
\frac{3}{4} - \frac{x + 1}{12} = \frac{2}{3} - \frac{x - 1}{6}
$

Multiplying by 12 you get:

Mr F says: 9 - (x + 1) = 8 - 2(x - 1)

9 - x + 1 = 8 - 2(x - 1) Mr F says: Should be 9 - x - 1 = 8 - 2(x - 1)

[snip]

..