# Need help for Algrebra test on Monday.

• Mar 7th 2008, 09:34 AM
Jarod_C
Need help for Algrebra test on Monday.
pie="π"

Take 0.025µ^4π² + 50µ²π^4 by 5µπ^3

Well there's the problem, and I have the answer, witch is (0.005µ^3 over π) + 10µπ. I'm just having a hard time doing the long division.

I've come up with many other answers, none of course being the right one. It's kind of a big favor to ask, but can someone explain the long division to me.
• Mar 7th 2008, 09:38 AM
colby2152
Quote:

Originally Posted by Jarod_C
pie="π"

Take 0.025µ^4π² + 50µ²π^4 by 5µπ^3

Well there's the problem, and I have the answer, witch is (0.005µ^3 over π) + 10µπ. I'm just having a hard time doing the long division.

I've come up with many other answers, none of course being the right one. It's kind of a big favor to ask, but can someone explain the long division to me.

Is this what you are trying to solve?

$\frac{0.25\mu^4 \pi^2 + 50\mu^2 \pi^4}{5\mu\pi^3}$
• Mar 7th 2008, 10:00 AM
Jarod_C
$
\frac{0.25\mu^4 \pi^2 + 50\mu^2 \pi^4}{5\mu\pi^3}
$
Yep, that's the one my life has come down to.
• Mar 7th 2008, 10:18 AM
colby2152
$
\frac{0.25\mu^4 \pi^2 + 50\mu^2 \pi^4}{5\mu\pi^3}
$

$
\frac{0.25\mu^4 \pi^2}{5\mu\pi^3} +\frac{50\mu^2 \pi^4}{5\mu\pi^3}
$

$
\frac{\mu^3}{20\pi} + 10\mu \pi
$