1. ## Find solutions

Find all real-number solutions. Round your result(s) to the second decimal place. Verify that your results satisfy the equation.

1.)

$5b^2=45$

$b=3$

2.)

$\frac{b^9}{b^6}=\frac{2}{9}$

$b=.61$

2. For the first, how about b = -3? Remember when you take a square root, you get two answers (generally; not if the number you're taking the root of is 0, I guess.)

3. Okay. What about the second problem? Was my answer correct? I was really unsure of it.

4. Yep, I also got .61.

$\frac{b^9}{b^6} = b^3 = \frac{2}{9}$

so:

$b = \sqrt[3]{\frac{2}{9}}$

which is .61, rounded to the nearest hundredth.