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Math Help - hyperbolic function problem

  1. #1
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    hyperbolic function problem

    can anybody help me with the question below??
    simplify:
    sech(3log (x))

    i dont have a clue how to simplify this kind of question, anybody give me hand?>>
    thanx!!
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by xixihaha View Post
    can anybody help me with the question below??
    simplify:
    sech(3log (x))



    i dont have a clue how to simplify this kind of question, anybody give me hand?>>
    thanx!!

    Alright I fixed it (I think)

    sech(x)=\frac{2}{e^x+e^{-x}}

    note:

    e^{3log{x}}=e^{log{x^3}}=e^{\frac{lnx^3}{ln10}}=\l  eft(e^{lnx^3}\right)^{\frac{1}{ln10}}=x^\frac{3}{l  n10}

    evaluating the above we get..

    sech(3log(x))=\frac{2}{e^{logx^3}+e^{-logx^3}}

    simplifying with the above


    \frac{2}{e^{logx^3}+e^{-logx^3}}=\frac{2}{x^\frac{3}{ln10}+x^\frac{-3}{ln10}}=\frac{2x^\frac{3}{ln10}}{x^\frac{6}{ln10  }+1}
    Last edited by TheEmptySet; March 6th 2008 at 02:50 PM. Reason: I simplifyied wrong in my note
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