For this question
(64x^3 + 0x + 8) / (4x +2)
I got 16x^2 -8X + 6
Am I right
I just did the calculations and got the answer to be $\displaystyle 16x^2 - 8x +4$. I'll post up my method, wait a few minutes.
EDIT: I don't know how to use latex to do long division so I'll show how my answer is correct by opening up the brackets to obtain the original equation. My original method was using long division and divided $\displaystyle 64x^3 + 8$ by $\displaystyle 4x + 2$.
$\displaystyle (4x + 2)(16x^2 - 8x + 4)$
$\displaystyle = 64 x^3 - 32x^2 + 16x + 32x^2 - 16x + 8$
$\displaystyle = 64x^3 + 8$
$\displaystyle \frac{{64x^3 + 8}}
{{4x + 2}} = \frac{{8\left( {8x^3 + 1} \right)}}
{{2\left( {2x + 1} \right)}} =$$\displaystyle \frac{{4\left( {8x^3 + 1} \right)}}
{{\left( {2x + 1} \right)}} = \frac{{4\left( {2x + 1} \right)\left( {4x^2 - 2x + 1} \right)}}
{{\left( {2x + 1} \right)}} = 4\left( {4x^2 - 2x + 1} \right) = 16x^2 - 8x + 4$