Results 1 to 3 of 3

Math Help - I need help!

  1. #1
    Newbie
    Joined
    Mar 2008
    Posts
    6

    I need help!

    Ok I know how to do problems like this. (18x^2 - 3x - 10) / (3x -2)

    But I don't know how to do problems like this.

    (8x^3 -27) / (2x-3) Please help. Do I just substitute 0's?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Behold, the power of SARDINES!
    TheEmptySet's Avatar
    Joined
    Feb 2008
    From
    Yuma, AZ, USA
    Posts
    3,764
    Thanks
    78
    Quote Originally Posted by cleanwithit06 View Post
    Ok I know how to do problems like this. (18x^2 - 3x - 10) / (3x -2)

    But I don't know how to do problems like this.

    (8x^3 -27) / (2x-3) Please help. Do I just substitute 0's?

    There are lots of things that can do to it, but I am guessing that you want to factor and reduce.

    8x^3-27 is the difference of cubes so it factors into..

    \frac{(2x-3)(4x^2+6x+9)}{(2x-3)}=(4x^2+6x+9)
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Mar 2008
    Posts
    6
    Thankyou so much for your reply.
    Follow Math Help Forum on Facebook and Google+


/mathhelpforum @mathhelpforum