# Thread: I need help!

1. ## I need help!

Ok I know how to do problems like this. (18x^2 - 3x - 10) / (3x -2)

But I don't know how to do problems like this.

(8x^3 -27) / (2x-3) Please help. Do I just substitute 0's?

2. Originally Posted by cleanwithit06
Ok I know how to do problems like this. (18x^2 - 3x - 10) / (3x -2)

But I don't know how to do problems like this.

(8x^3 -27) / (2x-3) Please help. Do I just substitute 0's?

There are lots of things that can do to it, but I am guessing that you want to factor and reduce.

$8x^3-27$ is the difference of cubes so it factors into..

$\frac{(2x-3)(4x^2+6x+9)}{(2x-3)}=(4x^2+6x+9)$

3. Thankyou so much for your reply.