Graphing Functions...

• Mar 4th 2008, 08:42 PM
Morzilla
Graphing Functions...
I am trying to understand Quadratics Functions but I got lost whilst working on the homework....

I am asked to graph the function $f$ by starting with the of $y=x^2$ and using transformation.....

Ok I am asked to solve this;

$f(x)=\frac{1}{4}x^2$

My question is this, if x equals 1, then is 1 added to the 1/4 or multiplied to the 1/4?

Thank you all!
(Handshake)
• Mar 4th 2008, 09:00 PM
quarks
I'm not entirely sure I understand your question. Judging by the equation given, it's multiplied. The graph for $f(x)= \frac{1}{4}x^2$ will look like a squashed version of $f(x)=x^2$. That is, it'll be compressed by a factor of four.
• Mar 4th 2008, 09:14 PM
Morzilla
Quote:

Originally Posted by quarks
I'm not entirely sure I understand your question. Judging by the equation given, it's multiplied. The graph for $f(x)= \frac{1}{4}x^2$ will look like a squashed version of $f(x)=x^2$. That is, it'll be compressed by a factor of four.

ok so then if x=1 then the function would like this...?!

$F(1)=\frac{1}{4}(1)^2$ Ok. then knowing that $(1)^2 = 1$ then does the function look like this?

$F(1)=\frac{1}{4}1$ or $F(1)=\frac{1}{4}(1)$

thanks