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find the first eight numbers of the arithmetic sequence in which the sum of the first and seventh terms is 40 and the product of the first and fourth terms is 160
we cannot give you a full solution, of course, because you have to hand this in. i will give you a hint.
recall that the terms of an arithmetic series are of the form
$\displaystyle a_n = a_1 + (n - 1)d$ for $\displaystyle n = 1,2,3,...$
where $\displaystyle a_n$ is the nth term, $\displaystyle n$ is the current number of the term, $\displaystyle a_1$ is the first term, and $\displaystyle d = a_2 - a_1 = a_3 - a_2 = ...$ is the common difference.
use that to find the formula for the first 8 terms, then formulate them as the question asked to find what the question asked for
example, the first term is $\displaystyle a_1$
the second is $\displaystyle a_2 = a_1 + d$
the third is ...