I have two questions im stuck on...

#1 Find the value(s) for k for which 2(x-1)^2+2k=10
(a)exactly one real solution
(b)no real solution

#2
(a)Enter the following function into the graph menu on you calculator
2X^2+81200=2Y-800X
(b)Graph this function and copy it on to this page clearly labeling any significant features
(c)Using your calculator move the table menu, set a DOMAIN to 0<X<10 with a pitch of 2 and produce a table
(d)What is the last entry?
(e)What does it represent?
(f)Describe how we would find f(2.15) using these table functions

thank you!

2. Originally Posted by NESS.
I have two questions im stuck on...

#1 Find the value(s) for k for which 2(x-1)^2+2k=10
(a)exactly one real solution
(b)no real solution

...
Solve the equation for x:

$\displaystyle 2(x-1)^2+2k=10 ~\implies~ (x-1)^2 = \frac12 \cdot (10-2k)~\implies~ |x-1| = \sqrt{5-k}$

to (a): There exists only one real solution if the RHS equals zero that means: $\displaystyle k = 5$

to (b): If the radical is negative then you don't get a real solution: $\displaystyle k > 5$

to #2: You should mention which model of calculator you use ...