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- Mar 1st 2008, 11:08 PM #1

- Joined
- Aug 2007
- Posts
- 11

## Help: f(x)=0

Intro Calculus help

f(x) = x^2+4x-5

Find x such that f(x) = 0

I know it would be:

x^2+4x-5 = 0

(x+5)(x-1)=0

So,the answer would be**x=-5**or**x=1**.

But how would I explain that the signs (+ and -) would switch around, as I have to give full working out?

Thanks in advance

- Mar 2nd 2008, 12:14 AM #2

- Mar 2nd 2008, 12:15 AM #3