(2x^2 - 3/x)^18
how can I find the 16th term and follow up by finding the term that is independent of x?
The 16th term of $\displaystyle (a+b)^{18}$ is,Originally Posted by Stuart
$\displaystyle {18 \choose 15}a^{15}b^3$
Over here $\displaystyle a=2x^2,b=-3/x$
Thus,
$\displaystyle {18 \choose 15}(2x^2)^{15}(-3/x)^3=-816(2^{15}x^{30})\cdot \frac{3^3}{x^3}=-815\cdot 2^{15} \cdot 3^3\cdot x^{27}$