I need help on this problem please. ((2^3 m^2 n^-2) / p^-4))^2 Thank you
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I need help on this problem please. I forgot a parenthesis. ((2^3 m^2 n^-2) / (p^-4))^2 Thank you
$\displaystyle \left(\frac{(2^3\;m^2\;n^{-2})}{(p^{-4})}\right)^2$ $\displaystyle \frac{64\;m^4\;n^{-4}}{p^{-8}}$ $\displaystyle \frac{64\;m^4\;p^8}{n^4}$
Originally Posted by OzzMan $\displaystyle \left(\frac{(2^3\;m^2\;n^{-2})}{(p^{-4})}\right)^2$ $\displaystyle \frac{64\;m^4\;n^{-4}}{p^{-8}}$ $\displaystyle \frac{64\;m^4\;p^8}{n^4}$ I had that but just was not confident in it being right.
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