exponents

**blodgett** · March 1st 2008, 05:10 PM

I need help on this problem please.

((2^3 m^2 n^-2) / p^-4))^2

Thank you

**blodgett** · March 1st 2008, 05:50 PM

I need help on this problem please.

I forgot a parenthesis.

((2^3 m^2 n^-2) / (p^-4))^2

Thank you

**OzzMan** · March 1st 2008, 06:08 PM

$\left(\frac{(2^3\;m^2\;n^{-2})}{(p^{-4})}\right)^2$

$\frac{64\;m^4\;n^{-4}}{p^{-8}}$

$\frac{64\;m^4\;p^8}{n^4}$

**blodgett** · March 2nd 2008, 03:25 AM

Originally Posted by OzzMan

$\left(\frac{(2^3\;m^2\;n^{-2})}{(p^{-4})}\right)^2$

$\frac{64\;m^4\;n^{-4}}{p^{-8}}$

$\frac{64\;m^4\;p^8}{n^4}$

I had that but just was not confident in it being right.

Thread: exponents