A circus performance was attended by 120 people who paid a total of $120. The men paid $5, the women paid $2 and the children paid 10c.

How many men, how many women and how many children went to the circus?

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- Feb 29th 2008, 11:30 PM #1elite_snowmanGuest

- Feb 29th 2008, 11:43 PM #2
Solve simultaneously for all integer solutions that satisfy $\displaystyle 0 \leq x \leq 120$, $\displaystyle 0 \leq y \leq 120$ and $\displaystyle 0 \leq z \leq 120$:

x + y + z = 120

5x + 2y + 0.1z = 120

Note that the number of children must be a multiple of 10 ......