the sum of three consecutive terms of an arithmetic progression is 21.if these numbers are increased by 1,3, and 10 respectively, the resulting numbers form consecutive terms of a geometric proression. Find the numbers
the sum of three consecutive terms of an arithmetic progression is 21.if these numbers are increased by 1,3, and 10 respectively, the resulting numbers form consecutive terms of a geometric proression. Find the number
bjhopper, can you solve this system?
$\displaystyle \begin{array}{l}
a + \left( {a + d} \right) + \left( {a + 2d} \right) = 21 \\
\frac{{a + 1}}{{a + d + 3}} = \frac{{a + d + 3}}{{a + 2d + 10}} \\
\end{array}
$