If

find

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- Feb 29th 2008, 06:02 AM #1

- Feb 29th 2008, 08:18 AM #2

This number is called Champernowne Constant.

It's given by

Since it's a transcendental number, I can't see a way to multiply it by 8..

- Feb 29th 2008, 02:01 PM #3
Break the number

*x*into chunks, where each chuck starts with a 0 and ends just before the next 0 (and must include some nonzero digits). Multiply each chunk by 8, and then add the chunks up.

For example, the first chunk is 0.1234567891. Multiply that by 8:

The second chunk is 01112131415161718192. Multiply that by 8:

Hence the first 31 digits (30 decimal places) of 8*x*is:

Now continue with the third chunk 022122232425262728293, fourth chunk 03132333435363738394, etc.