I may not be! But are you???? LOL
A cereal company puts a 10-cent coupon in every other box of cereal. It puts a pencil in every fifth package, and a coupon for a free hamburger in every eighth package. Out of the first 100 boxes, how many will have all three items – a coupon, a pencil and a free hamburger coupon?
Originally Posted by MathGeek06
If you find the LCM of 2,5,8 you get 40
so every 40 boxes will have all three items.
100 divied by 40 = 2 boxes will have all items.
How about this one? (This is the last one I promise)
Sam and Susan have only nickels and dimes. Sue has 35 cents, Sam has the same number of dimes as Sue has nickels and he has half as many nickels as Sue has dimes. How many nickels does Sue have?
Sue has either 5 nickels or 7 nickels.
Since Sam must have half as many nickels as Sue has dimes, Sue must have an even number of dimes (or else Sam would have 1/2 of a nickel). So, Sue either has:
0 dimes and 7 nickels
2 dimes and 5 nickels
(Since 4 dimes is 40 cents, which is too much.)
It's possible that the assumption is Sue has both nickels and dimes, but the problem doesn't state that explicitly - it says Sam and Sue have only nickels and dimes. Depending on how you read that, you could get only one answer (2,5) or both answers.
By logic there are only 4 possible combinations that add up to 35 cents.
1) 1 nickel + 3 Dimes
2) 3 nickels + 2 Dimes
3) 5 nickels + 1 Dime
4) 7 nickels + 0 Dimes
Choice 4 is out becuase it doesn't have any dimes. (She has both nickels and dimes)
Choice 1,3 are out because sam have half as many nickels as sue has dimes.
therefore she must have an even amount of dimes.
so choice #2 is our winner.
She has 3 Nickels and two Dimes