Hello Prove that the sum of k^2 from k=1 to n is equal to: (n^3)/3 + (n^2)/2 + n/6 The book provided a hint: k^3 -(k -1)^3 = 3k^2 -3k + 1. But I don't know how to use it. Thanks in advance
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Write this equation down for and add them. Then and
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