For what values of a there are exactly two real numbers that satify the equation: x^3 + (a-1)x^3 + (9-a)x - 9 = 0 ?
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x = { , , } So, 1 is a real number. Now pick an 'a' such that the 2nd and 3rd element are equal. Note: I only checked the 'a' in the real. There might be other ways of satisfying the question.
Last edited by paultwang; May 23rd 2005 at 08:37 AM.
Sorry but there's a typo, It should read x^3 + (a-1)x^2 + (9-a)x - 9 = 0 Instead of: x^3 + (a-1)x^3 + (9-a)x - 9 = 0 Thanks!
Make the 2nd and 3rd element equal:
Thanks a lot paultwang!
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