hi, i am having trouble understanding some simplification my book is using. They take [3x/(3x-2)] and turn it into 1+[2/(3x-2)], can someone please explain how they did that?
thank you
You can do a long division on it, or use a little trick:
$\displaystyle \frac{3x}{3x - 2} = \frac{3x - 2 + 2}{3x - 2} = \frac{3x - 2}{3x - 2} + \frac{2}{3x - 2}$
$\displaystyle = 1 + \frac{2}{3x - 2}$
Make sure you learn how to do the long division method as well.
-Dan