Simplify. $\displaystyle \frac{(3b^4c^{-1})(2b^{-7}c^{-8})}{42b^{-5}c^4}$ My answer: $\displaystyle \frac{1b^2}{7c^{13}}$ Is this right?
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Originally Posted by mt_lapin Simplify. $\displaystyle \frac{(3b^4c^{-1})(2b^{-7}c^{-8})}{42b^{-5}c^4}$ My answer: $\displaystyle \frac{1b^2}{7c^{13}}$ Is this right? Yes!
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