Hi sorry about the over flow of questions today just going over some stuff for and exam tomorrow.
how would you simplify the following fraction into a single fraction?
$\displaystyle \frac{x}{x^2+4x+3}-\frac{2}{x^2+3x+2}$
cheers
Hi sorry about the over flow of questions today just going over some stuff for and exam tomorrow.
how would you simplify the following fraction into a single fraction?
$\displaystyle \frac{x}{x^2+4x+3}-\frac{2}{x^2+3x+2}$
cheers
Hello,Originally Posted by dadon
1. Factorize the denominators. You'll get:
$\displaystyle x^2+4x+3 = (x+1)(x+3)$
$\displaystyle x^2+3x+2 = (x+1)(x+2)$
2. Thus the lcd = (x+1)(x+2)(x+3).
3. Transform the fractions and you'll get:
$\displaystyle \frac{x(x+2)}{(x+1)(x+2)(x+3)}-\frac{2(x+3)}{(x+1)(x+2)(x+3)}$
$\displaystyle \frac{x^2+2x-2x-6}{(x+1)(x+2)(x+3)}$ = $\displaystyle \frac{x^2-6}{(x+1)(x+2)(x+3)} $
Greetings
EB