# Thread: simplifying two fractions

1. ## simplifying two fractions

Hi sorry about the over flow of questions today just going over some stuff for and exam tomorrow.

how would you simplify the following fraction into a single fraction?

$\frac{x}{x^2+4x+3}-\frac{2}{x^2+3x+2}$

cheers

2. Originally Posted by dadon
Hi sorry about the over flow of questions today just going over some stuff for and exam tomorrow.

how would you simplify the following fraction into a single fraction?

$\frac{x}{x^2+4x+3}-\frac{2}{x^2+3x+2}$
cheers
Hello,

1. Factorize the denominators. You'll get:
$x^2+4x+3 = (x+1)(x+3)$
$x^2+3x+2 = (x+1)(x+2)$

2. Thus the lcd = (x+1)(x+2)(x+3).

3. Transform the fractions and you'll get:

$\frac{x(x+2)}{(x+1)(x+2)(x+3)}-\frac{2(x+3)}{(x+1)(x+2)(x+3)}$

$\frac{x^2+2x-2x-6}{(x+1)(x+2)(x+3)}$ = $\frac{x^2-6}{(x+1)(x+2)(x+3)}$

Greetings

EB

3. thanks earboth