Okay... Here's the question...
5^(x-2)=2^(3x+4)
Solve for x
Show steps plz
Thx in advance; i'm in a hurry!!!
$\displaystyle 5^{x-2}=2^{3x+4}$
$\displaystyle ln(5^{x-2})=ln(2^{3x+4})$
$\displaystyle (x-2)ln5=(3x+4)ln2$
$\displaystyle xln5-2ln5=3xln2+4ln2$
$\displaystyle xln5-3xln2=4ln2+2ln5$
$\displaystyle x(ln5-3ln2)=4ln2+2ln5$
$\displaystyle x=\frac{4ln2+2ln5}{ln5-3ln2}$