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Math Help - facotr

  1. #1
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    facotr

    what do you do with these? these are the only ones i dont get...
    (p-5)^2
    (x-y)^2
    (d-2e)^2
    (3p-5q)^2
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  2. #2
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    Quote Originally Posted by Graffitixgirl View Post
    what do you do with these? these are the only ones i dont get...
    (p-5)^2
    (x-y)^2
    (d-2e)^2
    (3p-5q)^2
    Um ok .. well it's the same as...

    (n)^2 = n x n

    sooo

    (n+1)^2 = (n+1)(n+1)

    glade to give the answers but try them yourself first=]

    (p-5)^2 = p^2 -10p + 25
    (x-y)^2 = x^2 - 2xy + y^2
    (d-2e)^2 = d^2 - 4de + 4e^2
    (3p-5q)^2 = 9p^2 - 30pq + 25q^2
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  3. #3
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    Quote Originally Posted by Graffitixgirl View Post
    what do you do with these? these are the only ones i dont get...
    (p-5)^2
    (x-y)^2
    (d-2e)^2
    (3p-5q)^2
    I assume that you should expand the bracket.

    If so there are 2 different ways to do it:

    1. Re-write the square as a product and multiply using the distribution rule

    (p-5)^2 = (p-5)(p-5)

    2. All 4 terms belong to one binomial formula:

    (a-b)^2 = a^2 - 2ab + b^2

    Plug in your terms and values into this formula and you'll get the result immediately.
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