what do you do with these? these are the only ones i dont get...

(p-5)^2

(x-y)^2

(d-2e)^2

(3p-5q)^2

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- Feb 21st 2008, 04:41 AMGraffitixgirlfacotr
what do you do with these? these are the only ones i dont get...

(p-5)^2

(x-y)^2

(d-2e)^2

(3p-5q)^2 - Feb 21st 2008, 04:46 AMCharbel
- Feb 21st 2008, 04:47 AMearboth
I assume that you should expand the bracket.

If so there are 2 different ways to do it:

1. Re-write the square as a product and multiply using the distribution rule

$\displaystyle (p-5)^2 = (p-5)(p-5)$

2. All 4 terms belong to one binomial formula:

$\displaystyle (a-b)^2 = a^2 - 2ab + b^2$

Plug in your terms and values into this formula and you'll get the result immediately.