what do you do with these? these are the only ones i dont get...
(p-5)^2
(x-y)^2
(d-2e)^2
(3p-5q)^2
Printable View
what do you do with these? these are the only ones i dont get...
(p-5)^2
(x-y)^2
(d-2e)^2
(3p-5q)^2
Um ok .. well it's the same as...Quote:
Originally Posted by Graffitixgirl
(n)^2 = n x n
sooo
(n+1)^2 = (n+1)(n+1)
glade to give the answers but try them yourself first=]
(p-5)^2 = p^2 -10p + 25
(x-y)^2 = x^2 - 2xy + y^2
(d-2e)^2 = d^2 - 4de + 4e^2
(3p-5q)^2 = 9p^2 - 30pq + 25q^2
I assume that you should expand the bracket.Quote:
Originally Posted by Graffitixgirl
If so there are 2 different ways to do it:
1. Re-write the square as a product and multiply using the distribution rule
2. All 4 terms belong to one binomial formula:
Plug in your terms and values into this formula and you'll get the result immediately.