What are the positive integers x for which
$\displaystyle 3^x + 4^x+ ... + (x+2)^x= (x+3)^x$
Wow, thats a tough question for pre algebra.
I am not good enough to prove it, but the answers are going to be 2 and 3.
$\displaystyle 3^2+4^2 = 9+16 = 25 = 5^2$
$\displaystyle 3^3+4^3+5^3 = 27+64+125 = 216 = 6^3$
After this, the (x+3)^x begins to outpace the sum of the lower powers, so it will continue to grow at a faster rate, and they won't ever catch back up. You can see it by charting the next few but like I said, I'm not good enough to prove it. Maybe someone else can prove it, I would love to see their thought process.