1. ## Check my work, please?

Hi! I'm a little confused about this problem, so I would appreciate help in solving it! I started it, but the answer doesn't make sense to me. Here's the problem:

Maria is 5 years younger than Betty. In 4 years, Maria will have 4 times the age Betty was 3 years ago. How old are they now?

Here's what I did:

Marķa's age: x
Betty's age: x+5
Marķas age 4 years from now: x+4
Betty's age 3 years ago: (x+5)-3
If Maria will be 4 times Betty's age 3 years ago, then: 4((x+5)-3)

So, I set up an equation: x+4=4((x+5)-3)

x+4=4x+20-12
x+4=4x+8
-8+4=4x-x
-4=3x
x= -3/4 ??

Help!

Thanks!

2. ## Re: Check my work, please?

Hi! I'm a little confused about this problem, so I would appreciate help in solving it! I started it, but the answer doesn't make sense to me. Here's the problem:

Maria is 5 years younger than Betty. In 4 years, Maria
will have 4 times the age
Betty was 3 years ago. How old are they now?

Thanks!
The problem also doesn't make sense. It's an impossible situation.

Here is a good fix for it. (Notice how I swap two names in one place.)

Maria is five years younger than Betty. In four years, Betty
will have four times the age Maria was three years ago.
How old are they now?

This amended problem works out with whole number answers.

3. ## Re: Check my work, please?

Originally Posted by greg1313
The problem also doesn't make sense. It's an impossible situation.

Here is a good fix for it. (Notice how I swap two names in one place.)

Maria is five years younger than Betty. In four years, Betty will have four times
the age Maria was three years ago. How old are they now?

This amended problem works out with whole number answers.
I knew something was fishy about it! It's from a manual (I'm studying for the College Board), and it has no answers, so... I guess that one was mis-written or something.

Thank you so much for your time!

4. ## Re: Check my work, please?

What did you get using Greg's corrections? Maria = 7 and Betty = 12 ?