Solve the Inequality

$\displaystyle \frac{T-8}{3-T}<0$

I got $\displaystyle T<8\quad -T<-3\quad \Longrightarrow T>3$

But the books answers were completely opposte of what I got. I'm not exactly sure where I messed up. The book got $\displaystyle T>8\quad T<3$

Anyone know what I'm doing wrong?