If the sum of the squares of two positive integers is 32 and their product is 9. What is the sum of two integers? x^2 + y^2 = 32 xy = 9 Is this the correct set up?
Follow Math Help Forum on Facebook and Google+
Originally Posted by harpazo If the sum of the squares of two positive integers is 32 and their product is 9. What is the sum of two integers? x^2 + y^2 = 32 xy = 9 Is this the correct set up? Set up correct...but there is NO solution to the problem itself. Try sum of squares = 34 and product = 15
Very good.
Correct setup. Just apply (x+y)^2=x^2+y^2+2xy ans is 50^1/2.
Last edited by mak29; Jan 5th 2019 at 10:56 AM.
Originally Posted by mak29 Correct setup. Just apply (x+y)^2=x^2+y^2+2xy ans is 50. Since $\displaystyle (x + y)^2 = 50$ then the sum $\displaystyle x + y = \pm \sqrt{50}$, which means at least one of x, y is not a positive integer. -Dan
Originally Posted by mak29 Correct setup. Just apply (x+y)^2=x^2+y^2+2xy ans is 50^1/2. Thanks.