Solve |2x - 1| + 5 > 2

My Work:

This is an absolute value inequality. Thus, we are not solving for x.

|2x - 1| + 5 > 2

|2x - 1| > 2 - 5

|2x - 1| > -3

At this point, I created two cases.

2x - 1 < 3

2x < 3 + 1

2x < 4

x < 4/2

x < 2

or

2x - 1 > -3

2x > -3 + 1

2x > -2

x > -2/2

x > -1

The solution to |2x - 1| + 5 > 2 is found here -1 < x < 2.

Correct?