1. ## Can someone explain me this please

I can't figure out the demonstration for alogbc= clogba

2. ## Re: Can someone explain me this please

Take logs (base $b$) and use $$\log_p q^r=r \log_p q$$

3. ## Re: Can someone explain me this please

Originally Posted by gabytzu
I can't figure out the demonstration for alogbc= clogba
Let's use the standard notation for natural logarithm, $\log(x)$.
Now $\log_b(c)=\dfrac{\log(a)}{\log(b)}~\&~\log_b(c)=\ dfrac{\log(c)}{\log(b)}$

Then is it true that $\log(a)\dfrac{\log(a)}{\log(b)}=\log(a)\dfrac{ \log(c)}{\log(b)}~?$

4. ## Re: Can someone explain me this please

Originally Posted by plato
let's use the standard notation for natural logarithm, $\log(x)$.
Now $\log_b(a)=\dfrac{\log(a)}{\log(b)}~\&~\log_b(c)= \dfrac{\log(c)}{\log(b)}$

then is it true that $\log(c)\dfrac{\log(a)}{\log(b)}=\log(a)\dfrac{ \log(c)}{\log(b)}~?$
Correction!