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Thread: Cross-sectional Area

  1. #1
    Senior Member harpazo's Avatar
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    Cross-sectional Area

    The cross-sectional area of a beam cut from a log with radius 1 foot is given by the function A(x) = (4x)(sqrt{1 - x^2}), where x represents the length, in feet, of half the base of the beam. Determine the cross-sectional area of the beam if the length of half the base of the beam is one-third of a foot.

    Let me see.

    There are 12 inches in one foot.

    So, (1/3)(12) = 4 inches.

    If x represents the length, in feet, of half the base of the beam, then I cannot let x = 4 inches. So, do I replace x with 1/3 in the given function and then simplify?
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  2. #2
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    Re: Cross-sectional Area

    Quote Originally Posted by harpazo View Post
    The cross-sectional area of a beam cut from a log with radius 1 foot is given by the function A(x) = (4x)(sqrt{1 - x^2}), where x represents the length, in feet, of half the base of the beam. Determine the cross-sectional area of the beam if the length of half the base of the beam is one-third of a foot.

    Let me see.

    There are 12 inches in one foot.

    So, (1/3)(12) = 4 inches.

    If x represents the length, in feet, of half the base of the beam, then I cannot let x = 4 inches. So, do I replace x with 1/3 in the given function and then simplify?
    Yes.
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  3. #3
    Senior Member harpazo's Avatar
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    Re: Cross-sectional Area

    Quote Originally Posted by Debsta View Post
    Yes.
    That's easy enough. I will work on this tomorrow.
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  4. #4
    Senior Member harpazo's Avatar
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    Re: Cross-sectional Area

    See picture for answer.
    Attached Thumbnails Attached Thumbnails Cross-sectional Area-mathmagic181209_2.png  
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  5. #5
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    Re: Cross-sectional Area

    Yes!!
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  6. #6
    Senior Member harpazo's Avatar
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    Re: Cross-sectional Area

    Quote Originally Posted by Debsta View Post
    Yes!!
    It certainly feels good to be right.
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