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Math Help - Algebra surd question please help

  1. #1
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    Algebra surd question please help

    Hi I need help with what should be a simple algebra problem, any help would be great thanks.


    the square root of 3 - the square root of 2 all over the sqaure root of (3 - the square root of 2)
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  2. #2
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    \frac{{\sqrt 3  - \sqrt 2 }}{{\sqrt {\sqrt 3  - \sqrt 2 } }}\frac{{\sqrt {\sqrt 3  - \sqrt 2 } }}{{\sqrt {\sqrt 3  - \sqrt 2 } }} = ?<br />
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  3. #3
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    The question is

    <br />
\frac{{\sqrt 3 - \sqrt 2 }}{{\sqrt {\ 3 - \sqrt 2 } }}<br />
    sorry I left an important bit out the answer has to be in the form

     a-b{{\sqrt c }}

    PS plato when you were multiplying the surd by the conjugate would the - not be outside the brackets, I'm abit confused
    Last edited by Ilusa; February 14th 2008 at 08:50 AM.
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Ilusa View Post
    The question is

    <br />
\frac{{\sqrt 3 - \sqrt 2 }}{{\sqrt {\sqrt 3 - \sqrt 2 } }}<br />
    sorry I left an important bit out the answer has to be in the form

     a-b{{\sqrt c }}

    PS plato when you were multiplying the surd by the conjugate would the - not be outside the brackets, I'm abit confused
    According to the general prescription there is a minus sign. But since it cancels out, most would not include it. For example, in Plato's hint:
    \frac{{\sqrt 3 - \sqrt 2 }}{{\sqrt {\sqrt 3 - \sqrt 2 } }} \cdot \frac{-{\sqrt {\sqrt 3 - \sqrt 2 } }}{-{\sqrt {\sqrt 3 - \sqrt 2 } }}

    = \frac{{\sqrt 3 - \sqrt 2 }}{{\sqrt {\sqrt 3 - \sqrt 2 } }}\frac{{\sqrt {\sqrt 3 - \sqrt 2 } }}{{\sqrt {\sqrt 3 - \sqrt 2 } }}

    Now just multiply things out and see what you get.

    -Dan
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  5. #5
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    the 3 on the denominator should not have the extra square root only the 2 should have

    The question is
    <br />
\frac{{\sqrt 3 - \sqrt 2 }}{{\sqrt {\ 3 - \sqrt 2 } }}<br />

    I multiplied it by <br />
\frac{{\sqrt {\ 3 - \sqrt 2 } }}{{\sqrt {\ 3 - \sqrt 2 } }}<br />

    and got <br />
\frac{{\sqrt {\ 3 - \sqrt 2 }.{\sqrt 3 - \sqrt 2 } }}{{ {\ 3 - \sqrt 2 } }}<br />

    where do you go form here I've factorised by ended up with the original equ
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  6. #6
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    anyone please?
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  7. #7
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by Ilusa View Post
    anyone please?
    Stop begging! Either someone will come along to help you or they won't.

    -Dan
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