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Thread: Rectangular Garden 2

  1. #1
    Member harpazo's Avatar
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    Rectangular Garden 2

    A gardener has 46 feet of fencing to be used to enclose a rectangular garden that has a border 2 feet wide surrounding it.

    A. If the length of the garden is to be twice the width, what will be the dimensions of the garden?

    B. What is the area of the garden?

    Length of garden = 2x
    Width of garden = x

    Dimensions = 2x + 4 for the length and x + 4 for the width.

    Part A Set Up:

    P = 2L + 2W

    2(2x + 4) + 2(x + 4) = 46

    Part B Set Up:

    After finding the dimensions of the garden, I then use the formula A = LW to find its area.

    Correct?
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  2. #2
    MHF Contributor

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    Re: Rectangular Garden 2

    Yes. What do you get as answers?
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  3. #3
    MHF Contributor
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    Re: Rectangular Garden 2

    Once more, please post your answers right away...less "running around"...
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  4. #4
    Member harpazo's Avatar
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    Re: Rectangular Garden 2

    Part A

    2(2x + 4) + 2(x + 4) = 46

    4x + 8 + 2x + 8 = 46

    6x + 16 = 46

    6x = 46 - 16

    6x = 30

    x = 30/6

    x = 5

    Length = 2x or 10

    Width = 5

    Part B:

    A = L•W

    A = 10(5)

    A = 50 ft^2
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