Results 1 to 10 of 10
Like Tree3Thanks
  • 1 Post By DenisB
  • 1 Post By DenisB
  • 1 Post By greg1313

Thread: Tennis Court

  1. #1
    Member harpazo's Avatar
    Joined
    Sep 2014
    From
    NYC
    Posts
    170
    Thanks
    1

    Tennis Court

    A regulation doubles tennis court has an area of 2808 square feet. If it is 6 feet longer than twice the width, determine the dimension of the court.

    Let x = width

    Let = 2x + 6

    Let area = A = 2808 ft^2

    A = LW

    2808 = (2x + 6)(x)

    Is this the correct equation set up? If not, why?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Joined
    Feb 2015
    From
    Ottawa Ontario
    Posts
    2,013
    Thanks
    388

    Re: Tennis Court

    Quote Originally Posted by harpazo View Post
    2808 = (2x + 6)(x)
    Is this the correct equation set up? If not, why?
    Correct; 2x^2 + 6x - 2808 = 0
    Divide by 2: x^2 + 3x - 1404 = 0
    Solve using quadratic equation...
    Thanks from harpazo
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member harpazo's Avatar
    Joined
    Sep 2014
    From
    NYC
    Posts
    170
    Thanks
    1

    Re: Tennis Court

    Quote Originally Posted by DenisB View Post
    Correct; 2x^2 + 6x - 2808 = 0
    Divide by 2: x^2 + 3x - 1404 = 0
    Solve using quadratic equation...
    Do you suggest the quadratic formula here?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    MHF Contributor
    Joined
    Feb 2015
    From
    Ottawa Ontario
    Posts
    2,013
    Thanks
    388

    Re: Tennis Court

    Yes! Unless you wanna try factoring...
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Member harpazo's Avatar
    Joined
    Sep 2014
    From
    NYC
    Posts
    170
    Thanks
    1

    Re: Tennis Court

    I decided to use the quadratic formula.

    Let length = 2x + 6

    Let width = x

    I found x to be 75.

    So, the width is 75 feet.

    The length is 2(75) + 6 or 156 feet.

    Something is wrong. You see, 156 x 75 does not equal the given area.
    Last edited by harpazo; Nov 4th 2018 at 07:56 AM.
    Follow Math Help Forum on Facebook and Google+

  6. #6
    MHF Contributor
    Joined
    Feb 2015
    From
    Ottawa Ontario
    Posts
    2,013
    Thanks
    388

    Re: Tennis Court

    (2x + 6)(x) = 2808
    2x^2 + 6x - 2808 = 0
    x^2 + 3x - 1404 = 0

    x = [-3 +- sqrt(3^2 - 4(-1404)] / 2

    That leads to x = 36 or x = -39, so x = 36

    How did you end up with x = 75?
    Thanks from harpazo
    Follow Math Help Forum on Facebook and Google+

  7. #7
    Member harpazo's Avatar
    Joined
    Sep 2014
    From
    NYC
    Posts
    170
    Thanks
    1

    Re: Tennis Court

    Quote Originally Posted by DenisB View Post
    (2x + 6)(x) = 2808
    2x^2 + 6x - 2808 = 0
    x^2 + 3x - 1404 = 0

    x = [-3 +- sqrt(3^2 - 4(-1404)] / 2

    That leads to x = 36 or x = -39, so x = 36

    How did you end up with x = 75?
    I made a math error in the radicand of the quadratic formula.
    Follow Math Help Forum on Facebook and Google+

  8. #8
    Member harpazo's Avatar
    Joined
    Sep 2014
    From
    NYC
    Posts
    170
    Thanks
    1

    Re: Tennis Court

    Radicand of quadratic formula:

    sqrt{3^2 - 4(-1404)}

    sqrt{9 + 5616}

    sqrt{5625} = 75

    This is how I got 75.

    (-3 + 75)/2

    72/2 = 36

    I now see that x = 36, which is the width's length.

    Length = 2(36) + 6 = 72 + 6 = 78.

    Width = 36 feet

    Length = 78 feet
    Follow Math Help Forum on Facebook and Google+

  9. #9
    Member
    Joined
    Dec 2016
    From
    Earth
    Posts
    214
    Thanks
    97

    Re: Tennis Court

    Quote Originally Posted by harpazo View Post
    A regulation doubles tennis court has an area of 2808 square feet. If the length is 6 feet longer than twice the width, determine the dimensions of the court.

    Let x = width

    Let 2x + 6 = the length
    harpazo, it's good to proofread for missing words.
    Thanks from harpazo
    Follow Math Help Forum on Facebook and Google+

  10. #10
    Member harpazo's Avatar
    Joined
    Sep 2014
    From
    NYC
    Posts
    170
    Thanks
    1

    Re: Tennis Court

    I am speeding through the textbook and thus messing up with the posted information.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Tennis Court Problem
    Posted in the Statistics Forum
    Replies: 1
    Last Post: Jun 10th 2009, 04:28 AM

/mathhelpforum @mathhelpforum