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Math Help - Difficult Indice Problems

  1. February 12th 2008, 11:25 PM #1
    acevipa
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    Difficult Indice Problems

    Simplify:

    \frac{12^x + 1} {6^{2x}+3^x}
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  2. February 12th 2008, 11:41 PM #2
    earboth
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    Quote Originally Posted by acevipa View Post
    Simplify:

    \frac{12^x + 1} {6^{2x}+3^x}
    \frac{12^x + 1} {6^{2x}+3^x} = \frac{12^x + 1} {36^x+3^x} = \frac{12^x + 1} {12^x \cdot 3^x+3^x} = \frac{12^x + 1} {3^x(12^x +1)} = \frac1{3^x}
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