Thread: Difficult Indice Problems

Simplify:

$\displaystyle \frac{12^x + 1} {6^{2x}+3^x}$

Originally Posted by acevipa

Simplify:

$\displaystyle \frac{12^x + 1} {6^{2x}+3^x}$

$\displaystyle \frac{12^x + 1} {6^{2x}+3^x} = \frac{12^x + 1} {36^x+3^x} = \frac{12^x + 1} {12^x \cdot 3^x+3^x} = \frac{12^x + 1} {3^x(12^x +1)} = \frac1{3^x}$