1. ## Difficult Indice Problems

Simplify:

$\displaystyle \frac{12^x + 1} {6^{2x}+3^x}$

2. Originally Posted by acevipa
Simplify:

$\displaystyle \frac{12^x + 1} {6^{2x}+3^x}$
$\displaystyle \frac{12^x + 1} {6^{2x}+3^x} = \frac{12^x + 1} {36^x+3^x} = \frac{12^x + 1} {12^x \cdot 3^x+3^x} = \frac{12^x + 1} {3^x(12^x +1)} = \frac1{3^x}$

### maths indicice problems

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