Originally Posted by

**alexcordero** Hello all!

I'm preparing for an Algebra test on Monday. I understand that $\displaystyle (2)^{-3} = \frac {1}{2^3}$ ultimately resulting in $\displaystyle \frac{1}{8}$ and I understand "why." Our teacher gave me a really good explanation starting with $\displaystyle (2)^{0}=1$ and worked down from there, I finally got it!

But what I don't seem to understand is why, $\displaystyle \Big( \frac{2}{z}\Big)^{-3}=\frac{z^3}{8}$. If I had to break it down I would start with, $\displaystyle \Big( \frac{2}{z}\Big)^{-3} = \Big( \frac{{2^{-3}}}{{z^{-3}}} \Big)$