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Thread: Arithmetic series of mean, median and mode

  1. #1
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    Arithmetic series of mean, median and mode

    http://prntscr.com/kufchq I got 25 , 15/7 and 1, can anyone check to see if I made a mistake or if I missed an answer?

    If x>=5: median=4.5
    mean=(31+x)/8
    mode=2

    If mean=-0.5: x=-35, Impossible
    If mean=3.25: x=-5, impossible
    If mean=7: x=25, Possible
    If 2=<x=<5: median=(4+x)/2
    mean= (31+x)/8
    mode=2
    If mean<median<mode: x=15/7, Possible (Extraneous)
    If mean<mode<median: x=-3, Impossible
    If mode<mean<median: x=15, Impossible
    If mode<median<mean: x=15/7, Possible
    If median<mode<mean:x=-3, Impossible
    If median<mean<mode: x=15, Impossible

    If x<2: median=3
    mean=(31+x)/8
    mode=2
    If mean=1: x=-23,Impossible
    If mean=2.5: x=-11,Impossible
    If mean=4: x=1, Possible

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  2. #2
    MHF Contributor
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    Re: Arithmetic series of mean, median and mode

    Those 3 are good answers. I didn't check for further ones.
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