Y^2 + x + 2y=5. I think it's x=-4p (y+1)^2 +5. Not sure though.
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$y^2 + x + 2y = 5$ $x = -y^2 - 2y + 5$ $x = -(y^2 + 2y) + 5$ $x = -(y^2+2y+1-1)+5$ $x = -(y+1)^2+1+5$ $x = -(y+1)^2 + 6$
I'm going to barge in here with a quick note. Mathematics is "case sensitive" so the variable Y is not the same as the variable y. Originally Posted by Nfalconer Y^2 + x + 2y=5 -Dan