Need help getting this into standard form 3y^2-8x^2=48.
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Originally Posted by Nfalconer Need help getting this into standard form 3y^2-8x^2=48. $\large{\dfrac{y^2}{16}-\dfrac{x^2}{6}=1}$
I got center of (0,0) and a=4 b= 2.4 (or is it plus or minus 2.4) and c I got 4.7. Does that seem right?
And y=4/2.4x or y=-4/2.4x
And for foci I got (0,4.7) and (0,-4.7). I know u said no decimals but I'm practicing for a test next week and professor said use decimals.
Originally Posted by Nfalconer I got center of (0,0) and a=4 b= 2.4 (or is it plus or minus 2.4) and c I got 4.7. Does that seem right? Originally Posted by Nfalconer And y=4/2.4x or y=-4/2.4x Originally Posted by Nfalconer And for foci I got (0,4.7) and (0,-4.7). I know u said no decimals but I'm practicing for a test next week and professor said use decimals. You have been told not to use decimals. I guess you don't want our help. Bye Bye
Center (0,0) a=4 b=square root of 6, c=square root of 22. And foci of (0,square root of 22) and (0,- square root of 22) and y=4/square root of 22 and y=-4/square root of 22. Yes I do want your help please!
Sorry I ment y=4/square root of 6 x and y=-4/square root of 6. My bad