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Thread: I need help with this math review question!

  1. #1
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    I need help with this math review question!

    Solve 6z - 2(z+4)=3(9-z)
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  2. #2
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    Re: I need help with this math review question!

    really?

    just expand both sides out, simplify it, and solve it. It will just be a linear equation.

    you can do it by eye....

    Spoiler:
    $(6-2)z - 8 = 27 - 3z$

    $(6 - 2 + 3)z = (27+8)$

    $7z = 35$

    $z=5$
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  3. #3
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    Re: I need help with this math review question!

    Oh shoot, rookie error but it’s been a while �� thank you
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  4. #4
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    Re: I need help with this math review question!

    Personally, I would have done this in a more basic way:
    6z - 2(z+4)=3(9-z)
    6z- 2z- 8= 27- 3z
    4z- 8= 27- 3z
    Add 8+ 3z to both sides:

    4z+ 3z= 27+ 8
    7z= 35

    z= 35/7= 5.

    Check: if z= 5, 6z - 2(z+4)= 6(5)- 2(9)= 30- 18= 12 and 3(9- z)= 3(9- 5)= 3(4)= 12. Yes, those are equal.
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