Originally Posted by

**Jhevon** that's because you did the wrong thing. first off, i'd move the x's to thee right hand side, to avoid the -x. it's no big deal really, but i like my math to look aesthetically pleasing.

so, 2x + 5 = 3x - 1 .............subtract 2x from both sides.

=> 5 = 3x - 1 - 2x ..............simplify

=> 5 = x - 1 ......................now add 1 to both sides

=> 5 + 1 = x ......................simplify

=> x = 6

thus we have found the x-coordinate for which the lines intersect. to find the y-coordinate, plug the x-value we found into either equation.

say we decided to use y = 2x + 5

plug in x = 6, we get:

y = 2(6) + 5

=> y = 17

say we decided to use y = 3x - 1

plug in x = 6, we get:

y = 3(6) - 1

=> y = 17 again, aha!

so when x = 6, y = 17

thus the point of intersection is (6,17)