60^a=3 and 60^b=5. I have to find out the value of 12^((1-a-b)/(2-2b))? All i have figured out is 60^1-a-b=4 because 60^a+b=3*5=60/4, so 60^a+b-1=1/4, so 60^1-a-b=4. Don't know if it is relevant for this problem
60^a=3 and 60^b=5. I have to find out the value of 12^((1-a-b)/(2-2b))? All i have figured out is 60^1-a-b=4 because 60^a+b=3*5=60/4, so 60^a+b-1=1/4, so 60^1-a-b=4. Don't know if it is relevant for this problem