# Slope AND y-intercept!!

• Feb 11th 2008, 02:42 PM
KuddlyKero
Slope AND y-intercept!!
Gawsh Im stumped and I need help fast!(Nod)

I need to know the slope and the y-intercept of the following equations:

y= 3x + 5
y= -6x + 3
y= -3/4x - 1
y= 5/-4x
y= 7 + 4x
y= -x/5 + 6

(Oh yah the slashes are for fractions!)
• Feb 11th 2008, 02:54 PM
topher0805
1) $\displaystyle y = 3x + 5$

This equation is of the form $\displaystyle y = mx + b$, where $\displaystyle m$ is the slope and $\displaystyle b$ is the $\displaystyle y$-intercept.

Therefore, the slope is $\displaystyle 3$ and the $\displaystyle y$-intercept is $\displaystyle 5$.

2) $\displaystyle y= -6x + 3$

Same thing here. Slope is $\displaystyle -6$ and $\displaystyle y$-intercept is $\displaystyle 3$.

3) $\displaystyle y= -3/4x - 1$

Once again, same format. Slope is $\displaystyle -3/4$ and $\displaystyle y$-intercept is $\displaystyle -1$.

4) $\displaystyle y= 5/-4x$

Is this what you mean? $\displaystyle y = \frac {-5}{4}x$

If so, the slope is $\displaystyle \frac {-5}{4}$ and the $\displaystyle y$-intercept is $\displaystyle 0$.

Basically the same thing for each one. :)