# Multiples

• February 11th 2008, 12:39 PM
kmbrooks1
Multiples
I cant figure out the multiples of 6,7,8,and 12
• February 11th 2008, 12:48 PM
topher0805
Are you just trying to find the set of all numbers that 6,7,8, and 12 all divide into without a remainder?

Start with 12. Anything that is divisible by will also be divisible by 6. So we have:

$12n$

Now, consider 8. 8 will go into even multiples of 12. So we have:

$24n$

Now, consider 7. 7 only goes into seven multiples of 12 (7*12, 14*12, 21*12, etc.). 7*12 = 84, but 8 only goes into even multiples of 12. So we have:

$168n$
• February 21st 2008, 12:44 PM
xifentoozlerix
6,7,8,12

lcm(6,8,12)=24
lcm(24,7)=168
• February 21st 2008, 04:13 PM
kmbrooks1
thx so much
thx u so much i needed tht!!!