Results 1 to 2 of 2

Math Help - Quadratic Equation Problems

  1. #1
    Senior Member
    Joined
    Feb 2008
    Posts
    297

    Quadratic Equation Problems

    1) Solve by factoring:

    (u+3)/(2u-7)=(2u-1)/(u-3)

    2) Find the exact solution to:

    2(k-1)]=(4-5k)/(k+1)

    3) Solve this equation:

    (3t)/(t^2-6)=Sqrt3
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member topher0805's Avatar
    Joined
    Jan 2008
    From
    Vancouver
    Posts
    336
    1) \frac {u+3}{2u-7} = \frac {2u-1}{u-3}

    Cross Multiply to get:

    <br />
\frac {(u + 3)(u - 3)}{2u - 7} = 2u - 1

    Multiply both sides by 2u - 7:

    (u + 3)(u - 3) = (2u - 7)(2u - 1)

    Now multiply out:

    u^2 + 3u - 3u - 9 = 4u^2 - 2u - 14u + 7

    Move everything to one side, then simplify:

    -3u^2 + 16u -16 = 0

    Now use the quadratic equation to find the roots.

    2) 2k - 2 = \frac {4 - 5k}{k + 1}

    Multiply both sides by k + 1:

    (2k - 2)(k + 1) = 4 - 5k

    Multiply out:

    <br />
2k^2 + 2k - 2k - 2 = 4 - 5k

    Bring everything to one side, then simplify:

    2k^2 + 5k - 6 = 0

    Now use the quadratic equation.

    3)
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. two quadratic equation problems
    Posted in the Algebra Forum
    Replies: 1
    Last Post: July 12th 2010, 11:05 AM
  2. help with quadratic equation word problems
    Posted in the Algebra Forum
    Replies: 2
    Last Post: April 19th 2009, 10:58 AM
  3. problems with quadratic equation
    Posted in the Algebra Forum
    Replies: 7
    Last Post: January 13th 2009, 05:44 AM
  4. quadratic equation problems
    Posted in the Algebra Forum
    Replies: 2
    Last Post: August 1st 2008, 09:13 PM
  5. two quadratic equation problems
    Posted in the Algebra Forum
    Replies: 3
    Last Post: December 27th 2007, 01:38 AM

Search Tags


/mathhelpforum @mathhelpforum